3Points Estimating
last edited by: Abiola Banjoko on Sep 12, 2021 10:59 PM  login/register to edit this page  
3Points is a technique that involves people that are professional in the task we are estimating by this technique. In threepoint estimation, three figures are produced initially for every distribution that is required, based on prior experience or bestguesses: The first is a most likely (M)/best guess (BG) which is the average amount of work the task might take if the team member performed it 100 times. The second estimate is the pessimistic (P) estimate which is the amount of work the task might take if the negative factors they identified do occur. The third estimate is the optimistic (O) estimate which is the amount of work the task might take if the positive risks they identified do occur. ApplicationTwo popular formula: 1. Triangular distribution: Triangular Distribution: E = (o + m + p ) / 3 where E is Estimate; o = optimistic estimate; p = pessimistic estimate; m = most likely estimate 2. Beta (or PERT): Beta Distribution (PERT): E = (o + 4m + p ) / 6 The beta distribution is a weighted average in which more weight is given to the most likely estimate. This alteration to the formula and placing more weight on the most likely estimate is made to increase the accuracy of the estimate by making it follow the Normal Distribution shape. Hence, in most of the cases, the Beta (PERT) distribution has been proven to be more accurate than the 3Point triangular estimation. By using beta distribution you can determine the level of certainty of this prediction The variance is obtained by the difference between the pessimistic and the optimistic forecast divided by six squared. The variance is the square of the Standard deviation.
ExampleFor Activity A: o = 4 hours , m = 8 hours , p = 16 hours Triangular Distribution: E = (4 + 8 + 16 ) / 3 E = 28 / 3 E = 9.3 hours Beta Distribution (PERT): E = (4 + 4(8) + 16) / 6 E = 52 / 6 E = 8.7 hours The Standard Deviation is a measure of variability from the mean and is defined as (p  o)/6 so in the example above S.D = (16  4 )/6 = 12/6 = 2 hours This means that using the normal distribution function where there is a 68% of the probability of one SD range from the mean It means that 68% chance of the schedule having a duration of 8.7+/2 which is 6.7 to 10.7 hours Other Estimating Techniques
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last edited by: Abiola Banjoko on Sep 12, 2021 10:59 PM  login/register to edit this page  
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